$\frac{x^2-16x+60}{x^2-9x+18}$

asked by guest
on Nov 18, 2024 at 8:31 am



You asked:

Evaluate the expression: \(\frac{{x}^{2} - 16 x + 60}{{x}^{2} - 9 x + 18}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{{x}^{2} - 16 x + 60}{{x}^{2} - 9 x + 18} = \frac{x^{2} - 16 x + 60}{x^{2} - 9 x + 18} \)


Expanded

\[\frac{{x}^{2} - 16 x + 60}{{x}^{2} - 9 x + 18} = \frac{x^{2}}{x^{2} - 9 x + 18} - \frac{16 x}{x^{2} - 9 x + 18} + \frac{60}{x^{2} - 9 x + 18}\]


Factored

\[\frac{{x}^{2} - 16 x + 60}{{x}^{2} - 9 x + 18} = \frac{x - 10}{x - 3}\]