1 Find the equation of the tangent to:y = x - 2x ^ 2 + 3 at 2y = sqrt(x) + 1 at x = 4y = x ^ 3 - 5x at x = 1y = 4/(sqrt(x)) at (1, 4)y = 3/x - 1/(x ^ 2) at (-1,-4)y = 3x ^ 2 - 1/x x = - 1y = x - 2x ^ 2 + 3 at 2y = sqrt(x) + 1 at x = 4y = x ^ 3 - 5x at x = 1y = 4/(sqrt(x)) at (1, 4)y = 3/x - 1/(x ^ 2) at (-1,-4)y = 3x ^ 2 - 1/x x = - 1

asked by guest
on Nov 18, 2024 at 8:37 pm



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