Solve for x:
pi*y=(arccos(x)-x*sqrt(1-x^2))
asked by guest on Mar 29, 2025 at 5:02 pm
You asked:
MathBot Answer:
x4−x2+y2π2−2yπarccos(x)+arccos2(x)=0∧−∞<x∧x<∞x^{4} - x^{2} + y^{2} \pi^{2} - 2 y \pi \arccos{\left(x \right)} + \arccos^{2}{\left(x \right)} = 0 \wedge -\infty < x \wedge x < \inftyx4−x2+y2π2−2yπarccos(x)+arccos2(x)=0∧−∞<x∧x<∞