Solve for x

e^2x-e^4=e^x+1-e^x+3

asked by guest
on Mar 14, 2025 at 6:40 am



You asked:

Solve the equation e2xe4=ex+1ex+3{e}^{2} x - {e}^{4} = {e}^{x} + 1 - {e}^{x} + 3 for the unknown xx.

MathBot Answer:

The solution is: x=4+e4e27.9303972x = \frac{4 + e^{4}}{e^{2}} \approx 7.9303972


e2xe4=ex+1ex+3xe2e4=4xe2=4+e4x=4+e4e2\begin{aligned}{e}^{2} x - {e}^{4} &= {e}^{x} + 1 - {e}^{x} + 3\\x e^{2} - e^{4} &= 4\\x e^{2} &= 4 + e^{4}\\x &= \frac{4 + e^{4}}{e^{2}}\end{aligned}


ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.