2.1M/50,0000

asked by guest
on Mar 21, 2025 at 11:20 am



MathBot Answer:

The sum of 2.1M50\frac{2.1 M}{50} and 00000000 is:

=(2.1M50)+(0000)=M(1110+2)50=21M500\begin{aligned}&=\left(\frac{2.1 M}{50}\right) + \left(0000\right) \\\\ &= \frac{M \left(1 \cdot \frac{1}{10} + 2\right)}{50} \\\\ &= \frac{21 M}{500} \\\\\end{aligned}


The difference of 2.1M50\frac{2.1 M}{50} and 00000000 is:

=(2.1M50)(0000)=M(1110+2)50=21M500\begin{aligned}&=\left(\frac{2.1 M}{50}\right) - \left(0000\right) \\\\ &= \frac{M \left(1 \cdot \frac{1}{10} + 2\right)}{50} \\\\ &= \frac{21 M}{500} \\\\\end{aligned}


The product of 2.1M50\frac{2.1 M}{50} and 00000000 is:

=(2.1M50)(0000)=0\begin{aligned}&=\left(\frac{2.1 M}{50}\right) \cdot \left(0000\right) \\\\ &= 0 \\\\\end{aligned}


The quotient of 2.1M50\frac{2.1 M}{50} and 00000000 is:

=(2.1M50)(0000)=~M\begin{aligned}&= \frac{\left(\frac{2.1 M}{50}\right)}{\left(0000\right)} \\\\ &= \tilde{\infty} M \\\\\end{aligned}