4^x = 112, find x
You asked:
Solve the equation \[{4}^{x} = 112\] for the unknown \(x\).
MathBot Answer:
The solution is: \[x = 2 + \frac{\log{\left(7 \right)}}{\log{\left(4 \right)}} \approx 3.4036775\]
4^x = 112, find x
You asked:
MathBot Answer:
The solution is: \[x = 2 + \frac{\log{\left(7 \right)}}{\log{\left(4 \right)}} \approx 3.4036775\]