ln(sec2x)^(1/(x^2))
You asked:
Evaluate the expression: \({\ln\left( \sec\left( 2 x \right) \right)}^{\frac{1}{{x}^{2}}}\)
MathBot Answer:
\[{\ln\left( \sec\left( 2 x \right) \right)}^{\frac{1}{{x}^{2}}} = \log{\left(\sec{\left(2 x \right)} \right)}^{\frac{1}{x^{2}}}\]