$(m-n)^{2}$ +6*(m+n)+9

asked by guest
on Oct 20, 2024 at 5:38 am



You asked:

Evaluate the expression: \({\left( m - n \right)}^{2} + 6 \cdot \left(m + n\right) + 9\)

MathBot Answer:

Evaluated



\(\displaystyle {\left( m - n \right)}^{2} + 6 \cdot \left(m + n\right) + 9 = 6 m + 6 n + \left(m - n\right)^{2} + 9 \)


Expanded

\[{\left( m - n \right)}^{2} + 6 \cdot \left(m + n\right) + 9 = m^{2} - 2 m n + 6 m + n^{2} + 6 n + 9\]


Factored

\[{\left( m - n \right)}^{2} + 6 \cdot \left(m + n\right) + 9 = m^{2} - 2 m n + 6 m + n^{2} + 6 n + 9\]