13x-11y=6xy

asked by guest
on Oct 22, 2024 at 10:53 am



You asked:

Investigate the equation: \(13 x - 11 y = 6 x y\).

MathBot Answer:

The graph of the equation \(13 x - 11 y = 6 x y\) is a hyperbola.


The coordinates of its foci are: \(\left(- \frac{\sqrt{286}}{6} - \frac{11}{6}, \frac{13}{6} + \frac{\sqrt{286}}{6}\right)\) and \(\left(- \frac{11}{6} + \frac{\sqrt{286}}{6}, \frac{13}{6} - \frac{\sqrt{286}}{6}\right)\).

The coordinates of its vertices are: \(\left(- \frac{\sqrt{143}}{6} - \frac{11}{6}, \frac{\sqrt{143}}{6} + \frac{13}{6}\right)\) and \(\left(- \frac{11}{6} + \frac{\sqrt{143}}{6}, \frac{13}{6} - \frac{\sqrt{143}}{6}\right)\).

The asymptotes have equations: \(6 \sqrt{143} y - 13 \sqrt{143} = 0\) and \(- 6 \sqrt{143} x - 11 \sqrt{143} = 0\).