-2.719=\log _{10}\left(\frac{1}{4000}+x\cdot \frac{17}{100000}\:\right)

asked by guest
on Oct 08, 2024 at 8:12 pm



You asked:

Solve the equation \(-2.719 = \log_{10}\left( \frac{1}{4000} + x \cdot \frac{17}{100000} \right)\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = - \frac{25}{17} + \frac{100 \cdot 10^{\frac{281}{1000}}}{17} \approx 9.7638427\]

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