(32x^3  - 4x^2  + 3x - 23) ÷ (8x - 7)

asked by kheirigs
on Nov 25, 2024 at 2:30 pm



You asked:

Evaluate the expression: \(\frac{32 {x}^{3} - 4 {x}^{2} + 3 x - 23}{8 x - 7}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{32 {x}^{3} - 4 {x}^{2} + 3 x - 23}{8 x - 7} = \frac{32 x^{3} - 4 x^{2} + 3 x - 23}{8 x - 7} \)

Expanded

\[\frac{32 {x}^{3} - 4 {x}^{2} + 3 x - 23}{8 x - 7} = \frac{32 x^{3}}{8 x - 7} - \frac{4 x^{2}}{8 x - 7} + \frac{3 x}{8 x - 7} - \frac{23}{8 x - 7}\]

+ Submit Question