1 - ln(x) - 2x^2 = 0

asked by guest
on Jan 24, 2025 at 11:15 am



You asked:

Solve the equation 1−ln⁡(x)−2x2=01 - \ln\left( x \right) - 2 {x}^{2} = 0 for the variable xx.

MathBot Answer:

The solution is: x=e1−W(4e2)2≈0.78717856x = e^{1 - \frac{W\left(4 e^{2}\right)}{2}} \approx 0.78717856

WW is the Lambert WW function, defined as the multivalued inverse function of f(w)=wewf(w) = we^w for any complex number ww.

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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