x^2+4x+8/x+2
asked by guest on Mar 30, 2025 at 6:42 am
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MathBot Answer:
x2+4x+8x+2=x2+4x+2+8x\displaystyle {x}^{2} + 4 x + \frac{8}{x} + 2 = x^{2} + 4 x + 2 + \frac{8}{x} x2+4x+x8+2=x2+4x+2+x8
x2+4x+8x+2=(x2+2)(x+4)x{x}^{2} + 4 x + \frac{8}{x} + 2 = \frac{\left(x^{2} + 2\right) \left(x + 4\right)}{x}x2+4x+x8+2=x(x2+2)(x+4)