∫01(83x3e−x2)dx\int_{0}^{1}(\frac{8}{3} x^3e^{-x^2}) dx

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on Apr 13, 2025 at 12:54 pm



You asked:

Evaluate the integral: ∫0183x3e−x2dx\int_{0}^{1}{\frac{8}{3} {x}^{3} {e}^{-{x}^{2}}}dx

MathBot Answer:

Definite integral

∫0183x3e−x2dx=43−83e≈0.35232149020948714241193661290277\int_{0}^{1}{\frac{8}{3} {x}^{3} {e}^{-{x}^{2}}}dx = \frac{4}{3} - \frac{8}{3 e} \approx 0.35232149020948714241193661290277

ee is Euler's number, a mathematical constant that is approximately 2.718282.71828.

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