e^x=ln2

asked by guest
on Sep 21, 2024 at 1:40 am



You asked:

Investigate the equation: \({e}^{x} = \ln\left( 2 \right)\).

MathBot Answer:

The real solution is: \[x = \log{\left(\log{\left(2 \right)} \right)} \approx -0.36651292\]

The complex solutions are: \[\left\{2 n i \pi + \log{\left(\log{\left(2 \right)} \right)}\; \middle|\; n \in \mathbb{Z}\right\}\]

\(e\) is Euler's number, a mathematical constant that is approximately \(2.71828\).

\(i\) is the imaginary unit, defined as \(i^2 = -1\).

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