∑_(k=1)^(n) 1/(4x^(k)+1) = n/(2n+1)

asked by guest
on Nov 24, 2024 at 11:41 am



You asked:

Investigate the equation: \(\sum_{k = 1}^{n} {\frac{1}{4 {x}^{k} + 1}} = \frac{n}{2 n + 1}\).

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