given that $3^{x+1}$ = $7^{2x-4}$ find the value of x
You asked:
Solve the equation \({3}^{x + 1} = {7}^{2 x - 4}\) for the variable \(x\).
MathBot Answer:
The solution is: \[x = - \frac{4 \log{\left(7 \right)} + \log{\left(3 \right)}}{- 2 \log{\left(7 \right)} + \log{\left(3 \right)}} \approx 3.1799468\]
asked 2 days ago
active 2 days ago