Solve the non-homogeneous system, if 𝑋1 = (
1
0
1
) 𝑒−3𝑡 and 𝑋2 = (
10
−1
1
) 𝑒−4𝑡 are
solutions of the system:
𝑋′ = (
−4 1 1
1 5 −1
0 1 −3
) 𝑋 + (
0
−1
1
) 𝑒2𝑡
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