∂T/∂t = 3 ∂²T/∂x²
Boundary conditions:
T(0,t) = 5, T(2,t) = 6, 0 < x < 2, t > 0
Initial condition:
T(x,0) = x²
Mathbot Says...
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.
∂T/∂t = 3 ∂²T/∂x²
Boundary conditions:
T(0,t) = 5, T(2,t) = 6, 0 < x < 2, t > 0
Initial condition:
T(x,0) = x²
I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.