A=\:\begin{pmatrix}0\:&\:-2\:\\ \:\:\:1\:&\:3\end{pmatrix}\:\:\:\:\:B=\begin{pmatrix}3\:&2\:\\ \:\:\:\:-1\:&\:0\end{pmatrix}\:\:\:B^{-1}=\:kA\:where\:k\:is\:a\:rational\:number.\:Find\:k

asked by guest
on Sep 24, 2024 at 5:20 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


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