(n+5)(n+3)(n-1)

asked by guest
on Apr 01, 2025 at 12:45 pm



You asked:

Evaluate the expression: (n+5)(n+3)(n−1)\left(n + 5\right) \left(n + 3\right) \left(n - 1\right)

MathBot Answer:

Evaluated



(n+5)(n+3)(n−1)=(n−1)(n+3)(n+5)\displaystyle \left(n + 5\right) \left(n + 3\right) \left(n - 1\right) = \left(n - 1\right) \left(n + 3\right) \left(n + 5\right)

Expanded

(n+5)(n+3)(n−1)=n3+7n2+7n−15\left(n + 5\right) \left(n + 3\right) \left(n - 1\right) = n^{3} + 7 n^{2} + 7 n - 15

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