sin(π/2+nπ/2)
asked by guest on Nov 15, 2024 at 8:18 pm
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MathBot Answer:
sin(π2+nπ2)=cos(nπ2)\sin\left( \frac{\pi}{2} + \frac{n \pi}{2} \right) = \cos{\left(\frac{n \pi}{2} \right)}sin(2π+2nπ)=cos(2nπ)