x 4^{4}4 +y4^{4}4 -7x2^{2}2y2^{2}2
asked by guest on Mar 18, 2025 at 6:27 am
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x4+y4−7x2y2=x4−7x2y2+y4\displaystyle {x}^{4} + {y}^{4} - 7 {x}^{2} {y}^{2} = x^{4} - 7 x^{2} y^{2} + y^{4} x4+y4−7x2y2=x4−7x2y2+y4
x4+y4−7x2y2=(x2−3xy+y2)(x2+3xy+y2){x}^{4} + {y}^{4} - 7 {x}^{2} {y}^{2} = \left(x^{2} - 3 x y + y^{2}\right) \left(x^{2} + 3 x y + y^{2}\right)x4+y4−7x2y2=(x2−3xy+y2)(x2+3xy+y2)