94A+15B+C=758
91A+18B+C=775
You asked:
Solve the system of equations:\[\begin{aligned}94 A + 15 B + C &= 758\\91 A + 18 B + C &= 775\end{aligned}\]
MathBot Answer:
The system of equations has infinitely many solutions.
$$\begin{aligned}A &= \frac{673}{109} - \frac{C}{109}\\B &= \frac{3872}{327} - \frac{C}{109}\end{aligned}$$
\(C\) is a free variable.