2^x+x-1.6=0

asked by guest
on Jan 19, 2025 at 12:40 pm



You asked:

Solve the equation \({2}^{x} + x - 1.6 = 0\) for the variable \(x\).

MathBot Answer:

The solution is: \[x = \frac{-0.875491922159008050044598315055696652978420036845 + \frac{8 \log{\left(2 \right)}}{5}}{\log{\left(2 \right)}} \approx 0.33693215\]

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