Given x < 0 real and n is a natural number and is odd, let y = - n$\sqrt{\x}$. Prove that y $y^{n}$ = x (so that the

real number y is also called the nth root of x).

asked by guest
on Oct 22, 2024 at 1:31 am



Mathbot Says...

I wasn't able to parse your question, but the HE.NET team is hard at work making me smarter.


+ Submit Question