[1-tan(x/2)][1-sin x]/[1+tan(x/2)][ π\pi-2x]^3

x=n/2

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on Nov 14, 2024 at 10:16 pm



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Investigate the equation: (1−tan⁡(x2))(1−sin⁡(x))(1+tan⁡(x2))(π−2x)3x=n2\frac{\left(1 - \tan\left( \frac{x}{2} \right)\right) \left(1 - \sin\left( x \right)\right)}{\left(1 + \tan\left( \frac{x}{2} \right)\right) {\left( \pi - 2 x \right)}^{3} x} = \frac{n}{2}.
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