2(y+3)-5(y-1)=6

asked by guest
on Mar 31, 2025 at 1:27 am



You asked:

Solve the equation 2(y+3)−5(y−1)=62 \left(y + 3\right) - 5 \left(y - 1\right) = 6 for the variable yy.

MathBot Answer:

The solution is: y=53=1.6‾y = \frac{5}{3} = 1.\overline{6}

11−3y=6−3y=−5y=53\begin{aligned}11 - 3 y &= 6\\- 3 y &= -5\\y &= \frac{5}{3}\end{aligned}

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