(x+11)(x+1)(x+3)
asked by guest on Mar 29, 2025 at 7:21 am
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MathBot Answer:
(x+11)(x+1)(x+3)=(x+1)(x+3)(x+11)\displaystyle \left(x + 11\right) \left(x + 1\right) \left(x + 3\right) = \left(x + 1\right) \left(x + 3\right) \left(x + 11\right) (x+11)(x+1)(x+3)=(x+1)(x+3)(x+11)
(x+11)(x+1)(x+3)=x3+15x2+47x+33\left(x + 11\right) \left(x + 1\right) \left(x + 3\right) = x^{3} + 15 x^{2} + 47 x + 33(x+11)(x+1)(x+3)=x3+15x2+47x+33