412.8 divided by 2,4

asked by guest
on Jan 11, 2025 at 6:52 am



MathBot Answer:

The sum of \(\frac{412.8}{2}\) and \(4\) is:

\[\begin{aligned}&=\left(\frac{412.8}{2}\right) + \left(4\right) \\\\ &= 4 + \frac{8 \cdot \frac{1}{10} + 412}{2} \\\\ &= \frac{1052}{5} \\\\\end{aligned}\]

The difference of \(\frac{412.8}{2}\) and \(4\) is:

\[\begin{aligned}&=\left(\frac{412.8}{2}\right) - \left(4\right) \\\\ &= -4 + \frac{8 \cdot \frac{1}{10} + 412}{2} \\\\ &= \frac{1012}{5} \\\\\end{aligned}\]

The product of \(\frac{412.8}{2}\) and \(4\) is:

\[\begin{aligned}&=\left(\frac{412.8}{2}\right) \cdot \left(4\right) \\\\ &= \frac{4128}{5} \\\\\end{aligned}\]

The quotient of \(\frac{412.8}{2}\) and \(4\) is:

\[\begin{aligned}&= \frac{\left(\frac{412.8}{2}\right)}{\left(4\right)} \\\\ &= \frac{258}{5} \\\\\end{aligned}\]

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