6(a+2)+2(a-1)
asked by guest on Mar 25, 2025 at 10:36 am
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MathBot Answer:
6(a+2)+2(a−1)=8a+10\displaystyle 6 \left(a + 2\right) + 2 \left(a - 1\right) = 8 a + 10 6(a+2)+2(a−1)=8a+10
6(a+2)+2(a−1)=8a+106 \left(a + 2\right) + 2 \left(a - 1\right) = 8 a + 106(a+2)+2(a−1)=8a+10