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e^ylnxdx+ ye^x+y dy=0
asked by
guest
on Mar 22, 2025 at 12:19 am
You asked:
Investigate the equation:
e
y
ln
(
x
d
x
)
+
y
e
x
+
y
d
y
=
0
{e}^{y} \ln\left( x d x \right) + y {e}^{x} + y d y = 0
e
y
ln
(
x
d
x
)
+
y
e
x
+
y
d
y
=
0
.
+ Submit Question
