(TAxL)/L+A
asked by guest on Mar 17, 2025 at 4:33 am
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MathBot Answer:
TAxLL+A=ATx+A\displaystyle \frac{T A x L}{L} + A = A T x + A LTAxL+A=ATx+A
TAxLL+A=A(Tx+1)\frac{T A x L}{L} + A = A \left(T x + 1\right)LTAxL+A=A(Tx+1)