7-3i/6-2i
asked by guest on Mar 31, 2025 at 3:55 pm
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MathBot Answer:
7−3i6−2i=7−5i27 - \frac{3 i}{6} - 2 i = 7 - \frac{5 i}{2}7−63i−2i=7−25i
iii is the imaginary unit, defined as i2=−1i^2 = -1i2=−1.