4(3x-1)+3(3x+2)
asked by guest on Feb 01, 2025 at 11:08 am
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MathBot Answer:
4(3x−1)+3(3x+2)=21x+2\displaystyle 4 \left(3 x - 1\right) + 3 \left(3 x + 2\right) = 21 x + 2 4(3x−1)+3(3x+2)=21x+2
4(3x−1)+3(3x+2)=21x+24 \left(3 x - 1\right) + 3 \left(3 x + 2\right) = 21 x + 24(3x−1)+3(3x+2)=21x+2