factor 2(a+b)^3 -8(a+b)^2
asked by guest on Apr 06, 2025 at 9:10 am
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MathBot Answer:
The polynomial factors into the product: 2(a+b)3−8(a+b)2=2(a+b)2(a+b−4)2 {\left( a + b \right)}^{3} - 8 {\left( a + b \right)}^{2} = 2 \left(a + b\right)^{2} \left(a + b - 4\right)2(a+b)3−8(a+b)2=2(a+b)2(a+b−4)