Find dy/dx
When 2x+3y+cos x +cos y= 2
asked by guest on Mar 28, 2025 at 3:25 pm
MathBot Answer:
ddxy(x)[2x+3y+cos(x)+cos(y)=2]=2−sin(x)sin(y)−3\frac{d}{d x} y{\left(x \right)}\left[2 x + 3 y + \cos{\left(x \right)} + \cos{\left(y \right)} = 2\right]=\frac{2 - \sin{\left(x \right)}}{\sin{\left(y \right)} - 3}dxdy(x)[2x+3y+cos(x)+cos(y)=2]=sin(y)−32−sin(x)