x^2+4x-s=0

asked by guest
on Nov 26, 2024 at 3:17 am



You asked:

Investigate the equation: \({x}^{2} + 4 x - s = 0\).

MathBot Answer:

The graph of the equation \({x}^{2} + 4 x - s = 0\) is a parabola.


The coordinates of its vertex are: \(\left(-4, -2\right)\)

The coordinates of its focus are: \(\left(- \frac{15}{4}, -2\right)\)

The directrix has equation: \(4 s + 17 = 0\).

The parabola has parameterization: \[\begin{aligned}s\left(\theta\right) &= -4 + \theta^{2}\\x\left(\theta\right) &= -2 + \theta\end{aligned}\]