evaluate it e^x-e^-x/log(1+x)

asked by guest
on Oct 22, 2024 at 8:42 am



You asked:

Evaluate the expression: \({e}^{x} - \frac{{e}^{-x}}{\log\left( 1 + x \right)}\)

MathBot Answer:

Simplified: \[{e}^{x} - \frac{{e}^{-x}}{\log\left( 1 + x \right)} = e^{x} - \frac{e^{- x}}{\log{\left(x + 1 \right)}}\]

Factored: \[{e}^{x} - \frac{{e}^{-x}}{\log\left( 1 + x \right)} = \frac{\left(e^{2 x} \log{\left(x + 1 \right)} - 1\right) e^{- x}}{\log{\left(x + 1 \right)}}\]

+ Submit Question