if y= (csc x -cot x) (csc x + cot x ) , then dy/dx = ??

asked by guest
on Nov 10, 2024 at 1:48 am



MathBot Answer:

ddxy(x)=(−cot⁡(x)+csc⁡(x))(−cot⁡2(x)−cot⁡(x)csc⁡(x)−1)+(cot⁡(x)+csc⁡(x))(cot⁡2(x)−cot⁡(x)csc⁡(x)+1)\frac{d}{d x} y{\left(x \right)} = \left(- \cot{\left(x \right)} + \csc{\left(x \right)}\right) \left(- \cot^{2}{\left(x \right)} - \cot{\left(x \right)} \csc{\left(x \right)} - 1\right) + \left(\cot{\left(x \right)} + \csc{\left(x \right)}\right) \left(\cot^{2}{\left(x \right)} - \cot{\left(x \right)} \csc{\left(x \right)} + 1\right)

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