(3x^2-2x+2)/(x-8)

asked by guest
on Nov 25, 2024 at 4:22 pm



You asked:

Evaluate the expression: \(\frac{3 {x}^{2} - 2 x + 2}{x - 8}\)

MathBot Answer:

Evaluated



\(\displaystyle \frac{3 {x}^{2} - 2 x + 2}{x - 8} = \frac{3 x^{2} - 2 x + 2}{x - 8} \)

Expanded

\[\frac{3 {x}^{2} - 2 x + 2}{x - 8} = \frac{3 x^{2}}{x - 8} - \frac{2 x}{x - 8} + \frac{2}{x - 8}\]

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