3a³b² + 16ab + 8a²b³

asked by guest
on Mar 25, 2025 at 9:32 pm



You asked:

Evaluate the expression: 3a3b2+16ab+8a2b33 {a}^{3} {b}^{2} + 16 a b + 8 {a}^{2} {b}^{3}

MathBot Answer:

Evaluated



3a3b2+16ab+8a2b3=3a3b2+8a2b3+16ab\displaystyle 3 {a}^{3} {b}^{2} + 16 a b + 8 {a}^{2} {b}^{3} = 3 a^{3} b^{2} + 8 a^{2} b^{3} + 16 a b

Factored

3a3b2+16ab+8a2b3=ab(3a2b+8b2a+16)3 {a}^{3} {b}^{2} + 16 a b + 8 {a}^{2} {b}^{3} = a b \left(3 a^{2} b + 8 b^{2} a + 16\right)

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