lim 𝑥->1 (𝑥^2−1) / (𝑥^2−4*𝑥+3)
You asked:
Evaluate the expression: \(\lim_{x \to 1}{\frac{{x}^{2} - 1}{{x}^{2} - 4 x + 3}}\)
MathBot Answer:
\[\lim_{x \to 1}{\frac{{x}^{2} - 1}{{x}^{2} - 4 x + 3}} = -1\]
lim 𝑥->1 (𝑥^2−1) / (𝑥^2−4*𝑥+3)
You asked:
MathBot Answer: