(7(20) 1/3^{1/3}1/3-1) 1/3^{1/3}1/3
asked by guest on Nov 20, 2024 at 12:42 am
You asked:
MathBot Answer:
(7⋅2013−1)13=−1+7⋅2033≈2.62078620405183481170580181196641{\left( 7 \cdot {20}^{\frac{1}{3}} - 1 \right)}^{\frac{1}{3}} = \sqrt[3]{-1 + 7 \cdot \sqrt[3]{20}} \approx 2.62078620405183481170580181196641(7⋅2031−1)31=3−1+7⋅320≈2.62078620405183481170580181196641
(7⋅2013−1)13=7⋅203−13=−1+7⋅2033\begin{aligned}{\left( 7 \cdot {20}^{\frac{1}{3}} - 1 \right)}^{\frac{1}{3}}&=\sqrt[3]{7 \cdot \sqrt[3]{20} - 1}\\&=\sqrt[3]{-1 + 7 \cdot \sqrt[3]{20}}\end{aligned}(7⋅2031−1)31=37⋅320−1=3−1+7⋅320