(x-a³)/b²-bc+c² +(x-b³)/c²-ca+a²+(x-c³)/a²-ab+b=2(a+b+c)
You asked:
Investigate the equation: \(\frac{x - {a}^{3}}{{b}^{2}} - b c + {c}^{2} + \frac{x - {b}^{3}}{{c}^{2}} - c a + {a}^{2} + \frac{x - {c}^{3}}{{a}^{2}} - a b + b = 2 \cdot \left(a + b + c\right)\).