slope=-3/5, y-intercept=-2
You asked:
Find an equation of the line with slope \(-\frac{3}{5}\) and y-intercept \((0, -2)\).
MathBot Answer:
Standard Form:
$$\begin{aligned}Ax + By + C = 0\end{aligned}$$$$\begin{aligned} \text{Slope} &= -\frac{A}{B} \\ -\frac{A}{B} &= \frac{-3}{5} \\ A =& 3, B = 5 \end{aligned}$$$$\begin{aligned}3 x + 5 y + C &= 0 \\ 3(0) + 5(-2) + C &= 0 \\ 0 + -10 + C &= 0 \\ 0 + C &= 10 \\ C &= 10 \end{aligned}$$An equation of the line in standard form is: $3 x + 5 y + 10 = 0$.
Slope-Intercept Form:
$$\begin{aligned} y = mx+b\end{aligned}$$$$\begin{aligned}y &= - \frac{3}{5}x + b \\ -2 &= - \frac{3}{5} \times 0 + b \\ -2 &= 0 + b \\ b &= -2 \end{aligned}$$The slope-intercept form of the line is: $y = - \frac{3 x}{5} - 2$.