a(3u-v)+a(u+2v)
asked by guest on Jan 28, 2025 at 2:56 pm
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MathBot Answer:
a(3u−v)+a(u+2v)=a(3u−v)+a(u+2v)\displaystyle a\left( 3 u - v \right) + a\left( u + 2 v \right) = a \left(3 u - v\right) + a \left(u + 2 v\right) a(3u−v)+a(u+2v)=a(3u−v)+a(u+2v)
a(3u−v)+a(u+2v)=4ua+vaa\left( 3 u - v \right) + a\left( u + 2 v \right) = 4 u a + v aa(3u−v)+a(u+2v)=4ua+va
a(3u−v)+a(u+2v)=a(4u+v)a\left( 3 u - v \right) + a\left( u + 2 v \right) = a \left(4 u + v\right)a(3u−v)+a(u+2v)=a(4u+v)