(x²+7x+10)÷(x+2)
asked by guest on Mar 22, 2025 at 12:37 am
You asked:
MathBot Answer:
x2+7x+10x+2=x2+7x+10x+2\displaystyle \frac{{x}^{2} + 7 x + 10}{x + 2} = \frac{x^{2} + 7 x + 10}{x + 2} x+2x2+7x+10=x+2x2+7x+10
x2+7x+10x+2=x2x+2+7xx+2+10x+2\frac{{x}^{2} + 7 x + 10}{x + 2} = \frac{x^{2}}{x + 2} + \frac{7 x}{x + 2} + \frac{10}{x + 2}x+2x2+7x+10=x+2x2+x+27x+x+210
x2+7x+10x+2=x+5\frac{{x}^{2} + 7 x + 10}{x + 2} = x + 5x+2x2+7x+10=x+5