x ^ { 3 } -2x ^ { 2 } -4x+6 \div x-2
asked by guest on Mar 26, 2025 at 8:38 pm
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x3−2x2−4x+6x−2=x3−2x2−4x−2+6x\displaystyle {x}^{3} - 2 {x}^{2} - 4 x + \frac{6}{x} - 2 = x^{3} - 2 x^{2} - 4 x - 2 + \frac{6}{x} x3−2x2−4x+x6−2=x3−2x2−4x−2+x6
x3−2x2−4x+6x−2=x4−2x3−4x2−2x+6x{x}^{3} - 2 {x}^{2} - 4 x + \frac{6}{x} - 2 = \frac{x^{4} - 2 x^{3} - 4 x^{2} - 2 x + 6}{x}x3−2x2−4x+x6−2=xx4−2x3−4x2−2x+6