Is (5, 4) a solution to this system of inequalities?

15x − 20y ≥ –5

8x − 9y > 4

asked by guest
on Mar 29, 2025 at 7:05 pm



MathBot Answer:

False, (5, 4)\left( 5, \ 4\right) is not a solution of 15x20y5 and 8x9y>415 x - 20 y \geq -5 \text{ and } 8 x - 9 y > 4.


15x20y515(5)20(4)?555\begin{gathered}15 x - 20 y \geq -5\\15 \left(5\right) - 20 \left(4\right) \stackrel{?}{\ge} -5\\-5 \ge -5\end{gathered}8x9y>48(5)9(4)>?444\begin{gathered}8 x - 9 y > 4\\8 \left(5\right) - 9 \left(4\right) \stackrel{?}{\gt} 4\\4 \ngtr 4\end{gathered}